teachers = [

{"name": "张老师", "available_times": ["周六上午", "周日下午"]},

{"name": "李老师", "available_times": ["周六下午", "周日上午"]}

]

courses = [

{"name": "数学", "teacher": "张老师", "time": "周六上午", "classroom": "101"},

数据可视化

{"name": "英语", "teacher": "李老师", "time": "周六下午", "classroom": "102"}

]

def check_conflicts(schedule):

for i in range(len(schedule)):

for j in range(i + 1, len(schedule)):

if schedule[i]["teacher"] == schedule[j]["teacher"] and schedule[i]["time"] == schedule[j]["time"]:

return True

return False

def assign_courses(courses, teachers):

assigned_courses = []

for course in courses:

for teacher in teachers:

if course["teacher"] == teacher["name"] and course["time"] in teacher["available_times"]:

assigned_courses.append(course)

break

if check_conflicts(assigned_courses):

print("存在排课冲突，请重新调整。")

else:

print("排课成功！")

return assigned_courses